LeetCode-in-Java

3986. Number of Elapsed Seconds Between Two Times

Easy

You are given two valid times startTime and endTime, each represented as a string in the format "HH:MM:SS".

Return the number of seconds that have elapsed from startTime to endTime.

Example 1:

Input: startTime = “01:00:00”, endTime = “01:00:25”

Output: 25

Explanation:

endTime is 25 seconds ahead of startTime.

Example 2:

Input: startTime = “12:34:56”, endTime = “13:00:00”

Output: 1504

Explanation:

endTime is 25 minutes and 4 seconds ahead of startTime, which equals 1504 seconds.

Constraints:

• startTime.length == 8
• endTime.length == 8
• startTime and endTime are valid times in the format "HH:MM:SS"
• 00 <= HH <= 23
• 00 <= MM <= 59
• 00 <= SS <= 59
• endTime is not earlier than startTime

Solution

public class Solution {
    public int secondsBetweenTimes(String startTime, String endTime) {
        int startSec = 0;
        int endSec = 0;
        int sSec = 0;
        int eSec = 0;
        int colon = 2;
        for (int i = 0; i < 8; i++) {
            if (startTime.charAt(i) == ':') {
                startSec = (int) (startSec + sSec * Math.pow(60, colon));
                endSec = (int) (endSec + eSec * Math.pow(60, colon));
                colon--;
                sSec = 0;
                eSec = 0;
                continue;
            }
            sSec = sSec * 10 + (startTime.charAt(i) - '0');
            eSec = eSec * 10 + (endTime.charAt(i) - '0');
        }
        startSec = (int) (startSec + sSec * Math.pow(60, colon));
        endSec = (int) (endSec + eSec * Math.pow(60, colon));
        return endSec - startSec;
    }
}

This site is open source. Improve this page.