LeetCode-in-Java

3945. Digit Frequency Score

Easy

You are given an integer n.

The score of n is defined as the sum of d * freq(d) over all distinct digits d, where freq(d) denotes the number of times the digit d appears in n.

Return an integer denoting the score of n.

Example 1:

Input: n = 122

Output: 5

Explanation:

• The digit 1 appears 1 time, contributing 1 * 1 = 1.
• The digit 2 appears 2 times, contributing 2 * 2 = 4.
• Thus, the score of n is 1 + 4 = 5.

Example 2:

Input: n = 101

Output: 2

Explanation:

• The digit 0 appears 1 time, contributing 0 * 1 = 0.
• The digit 1 appears 2 times, contributing 1 * 2 = 2.
• Thus, the score of n is 2.

Constraints:

• 1 <= n <= 109

Solution

public class Solution {
    public int digitFrequencyScore(int n) {
        int sum = 0;
        while (n > 0) {
            sum += (n % 10);
            n /= 10;
        }
        return sum;
    }
}

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