LeetCode-in-Java

3387. Maximize Amount After Two Days of Conversions

Medium

You are given a string initialCurrency, and you start with 1.0 of initialCurrency.

You are also given four arrays with currency pairs (strings) and rates (real numbers):

You can perform any number of conversions, including zero, using rates1 on day 1, followed by any number of additional conversions, including zero, using rates2 on day 2.

Return the maximum amount of initialCurrency you can have after performing any number of conversions on both days in order.

Note: Conversion rates are valid, and there will be no contradictions in the rates for either day. The rates for the days are independent of each other.

Example 1:

Input: initialCurrency = “EUR”, pairs1 = [[“EUR”,”USD”],[“USD”,”JPY”]], rates1 = [2.0,3.0], pairs2 = [[“JPY”,”USD”],[“USD”,”CHF”],[“CHF”,”EUR”]], rates2 = [4.0,5.0,6.0]

Output: 720.00000

Explanation:

To get the maximum amount of EUR, starting with 1.0 EUR:

Example 2:

Input: initialCurrency = “NGN”, pairs1 = [[“NGN”,”EUR”]], rates1 = [9.0], pairs2 = [[“NGN”,”EUR”]], rates2 = [6.0]

Output: 1.50000

Explanation:

Converting NGN to EUR on day 1 and EUR to NGN using the inverse rate on day 2 gives the maximum amount.

Example 3:

Input: initialCurrency = “USD”, pairs1 = [[“USD”,”EUR”]], rates1 = [1.0], pairs2 = [[“EUR”,”JPY”]], rates2 = [10.0]

Output: 1.00000

Explanation:

In this example, there is no need to make any conversions on either day.

Constraints:

Solution

import java.util.ArrayDeque;

public class Example {
    public static void main(String[] args) {
        ArrayDeque<String> animals = new ArrayDeque<>();

        // "unshift" - Add an element at the beginning of the list
        animals.addFirst("Cat"); // Adds "Cat" at the front
        System.out.println("After unshift: " + animals);

        // "push" - Add an element to the end of the list
        animals.addLast("Dog"); // Adds "Dog" at the end
        System.out.println("After push: " + animals);

        // "shift" - Remove the first element from the list
        String shiftedAnimal = animals.removeFirst(); // Removes "Cat"
        System.out.println("After shift (removed): " + shiftedAnimal);
        System.out.println("List after shift: " + animals);

        // "pop" - Remove the last element from the list
        String poppedAnimal = animals.removeLast(); // Removes "Dog"
        System.out.println("After pop (removed): " + poppedAnimal);
        System.out.println("List after pop: " + animals);
    }
}