Easy
You are given an integer array nums
.
You replace each element in nums
with the sum of its digits.
Return the minimum element in nums
after all replacements.
Example 1:
Input: nums = [10,12,13,14]
Output: 1
Explanation:
nums
becomes [1, 3, 4, 5]
after all replacements, with minimum element 1.
Example 2:
Input: nums = [1,2,3,4]
Output: 1
Explanation:
nums
becomes [1, 2, 3, 4]
after all replacements, with minimum element 1.
Example 3:
Input: nums = [999,19,199]
Output: 10
Explanation:
nums
becomes [27, 10, 19]
after all replacements, with minimum element 10.
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 104
public class Solution {
public int minElement(int[] nums) {
int min = Integer.MAX_VALUE;
for (int x : nums) {
min = Math.min(min, solve(x));
}
return min;
}
private int solve(int x) {
int sum = 0;
while (x != 0) {
sum += x % 10;
x /= 10;
}
return sum;
}
}