LeetCode-in-Java

3227. Vowels Game in a String

Medium

Alice and Bob are playing a game on a string.

You are given a string s, Alice and Bob will take turns playing the following game where Alice starts first:

• On Alice’s turn, she has to remove any non-empty substring from s that contains an odd number of vowels.
• On Bob’s turn, he has to remove any non-empty substring from s that contains an even number of vowels.

The first player who cannot make a move on their turn loses the game. We assume that both Alice and Bob play optimally.

Return true if Alice wins the game, and false otherwise.

The English vowels are: a, e, i, o, and u.

Example 1:

Input: s = “leetcoder”

Output: true

Explanation:
Alice can win the game as follows:

• Alice plays first, she can delete the underlined substring in s = "**leetco**der" which contains 3 vowels. The resulting string is s = "der".
• Bob plays second, he can delete the underlined substring in s = "**d**er" which contains 0 vowels. The resulting string is s = "er".
• Alice plays third, she can delete the whole string s = "**er**" which contains 1 vowel.
• Bob plays fourth, since the string is empty, there is no valid play for Bob. So Alice wins the game.

Example 2:

Input: s = “bbcd”

Output: false

Explanation:
There is no valid play for Alice in her first turn, so Alice loses the game.

Constraints:

• 1 <= s.length <= 105
• s consists only of lowercase English letters.

Solution

public class Solution {
    public boolean doesAliceWin(String s) {
        for (int i = 0; i < s.length(); i++) {
            char curr = s.charAt(i);
            if (curr == 'a' || curr == 'e' || curr == 'i' || curr == 'o' || curr == 'u') {
                return true;
            }
        }
        return false;
    }
}

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