Hard
Given an array of integers nums and an integer k, return the number of subarrays of nums where the bitwise AND of the elements of the subarray equals k.
Example 1:
Input: nums = [1,1,1], k = 1
Output: 6
Explanation:
All subarrays contain only 1’s.
Example 2:
Input: nums = [1,1,2], k = 1
Output: 3
Explanation:
Subarrays having an AND value of 1 are: [**1**,1,2], [1,**1**,2], [**1,1**,2].
Example 3:
Input: nums = [1,2,3], k = 2
Output: 2
Explanation:
Subarrays having an AND value of 2 are: [1,**2**,3], [1,**2,3**].
Constraints:
1 <= nums.length <= 1050 <= nums[i], k <= 109public class Solution {
public long countSubarrays(int[] nums, int k) {
long ans = 0;
int left = 0;
int right = 0;
for (int i = 0; i < nums.length; i++) {
int x = nums[i];
for (int j = i - 1; j >= 0 && (nums[j] & x) != nums[j]; j--) {
nums[j] &= x;
}
while (left <= i && nums[left] < k) {
left++;
}
while (right <= i && nums[right] <= k) {
right++;
}
ans += right - left;
}
return ans;
}
}