Medium
You are given a string word of size n, and an integer k such that k divides n.
In one operation, you can pick any two indices i and j, that are divisible by k, then replace the substring of length k starting at i with the substring of length k starting at j. That is, replace the substring word[i..i + k - 1] with the substring word[j..j + k - 1].
Return the minimum number of operations required to make word k-periodic.
We say that word is k-periodic if there is some string s of length k such that word can be obtained by concatenating s an arbitrary number of times. For example, if word == “ababab”, then word is 2-periodic for s = "ab".
Example 1:
Input: word = “leetcodeleet”, k = 4
Output: 1
Explanation:
We can obtain a 4-periodic string by picking i = 4 and j = 0. After this operation, word becomes equal to “leetleetleet”.
Example 2:
Input: word = “leetcoleet”, k = 2
Output: 3
Explanation:
We can obtain a 2-periodic string by applying the operations in the table below.
i j word
0 2 etetcoleet
4 0 etetetleet
6 0 etetetetet
Constraints:
1 <= n == word.length <= 1051 <= k <= word.lengthk divides word.length.word consists only of lowercase English letters.import java.util.HashMap;
import java.util.Map;
public class Solution {
public int minimumOperationsToMakeKPeriodic(String word, int k) {
Map<Integer, Integer> map = new HashMap<>();
int n = word.length();
int max = 0;
for (int i = 0; i < n; i += k) {
int hash = 0;
for (int j = i; j < i + k; j++) {
int idx = word.charAt(j) - 'a';
hash = hash * 26 + idx;
}
int count = map.getOrDefault(hash, 0);
count++;
map.put(hash, count);
max = Math.max(max, count);
}
return n / k - max;
}
}