LeetCode-in-Java
3136. Valid Word
Easy
A word is considered valid if:
- It contains a minimum of 3 characters.
- It contains only digits (0-9), and English letters (uppercase and lowercase).
- It includes at least one vowel.
- It includes at least one consonant.
You are given a string word.
Return true if word is valid, otherwise, return false.
Notes:
'a','e','i','o','u', and their uppercases are vowels.- A consonant is an English letter that is not a vowel.
Example 1:
Input: word = “234Adas”
Output: true
Explanation:
This word satisfies the conditions.
Example 2:
Input: word = “b3”
Output: false
Explanation:
The length of this word is fewer than 3, and does not have a vowel.
Example 3:
Input: word = “a3$e”
Output: false
Explanation:
This word contains a '$' character and does not have a consonant.
Constraints:
1 <= word.length <= 20wordconsists of English uppercase and lowercase letters, digits,'@','#', and'$'.
Solution
public class Solution {
public boolean isValid(String word) {
if (word.length() < 3) {
return false;
}
boolean hasVowel = false;
boolean hasConsonant = false;
for (char c : word.toCharArray()) {
if (Character.isLetter(c)) {
char ch = Character.toLowerCase(c);
if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
hasVowel = true;
} else {
hasConsonant = true;
}
} else if (!Character.isDigit(c)) {
return false;
}
}
return hasVowel && hasConsonant;
}
}