Medium
You are given an array nums
of non-negative integers and an integer k
.
An array is called special if the bitwise OR
of all of its elements is at least k
.
Return the length of the shortest special non-empty subarray of nums
, or return -1
if no special subarray exists.
Example 1:
Input: nums = [1,2,3], k = 2
Output: 1
Explanation:
The subarray [3]
has OR
value of 3
. Hence, we return 1
.
Example 2:
Input: nums = [2,1,8], k = 10
Output: 3
Explanation:
The subarray [2,1,8]
has OR
value of 11
. Hence, we return 3
.
Example 3:
Input: nums = [1,2], k = 0
Output: 1
Explanation:
The subarray [1]
has OR
value of 1
. Hence, we return 1
.
Constraints:
1 <= nums.length <= 2 * 105
0 <= nums[i] <= 109
0 <= k <= 109
public class Solution {
public int minimumSubarrayLength(int[] nums, int k) {
int n = nums.length;
if (nums[0] >= k) {
return 1;
}
int res = Integer.MAX_VALUE;
for (int i = 1; i < n; i++) {
if (nums[i] >= k) {
return 1;
}
for (int j = i - 1; j >= 0 && (nums[i] | nums[j]) != nums[j]; j--) {
nums[j] |= nums[i];
if (nums[j] >= k) {
res = Math.min(res, i - j + 1);
}
}
}
if (res == Integer.MAX_VALUE) {
return -1;
}
return res;
}
}