Easy
You are given two 0-indexed integer arrays player1
and player2
, that represent the number of pins that player 1 and player 2 hit in a bowling game, respectively.
The bowling game consists of n
turns, and the number of pins in each turn is exactly 10
.
Assume a player hit xi
pins in the ith
turn. The value of the ith
turn for the player is:
2xi
if the player hit 10
pins in any of the previous two turns.xi
.The score of the player is the sum of the values of their n
turns.
Return
1
if the score of player 1 is more than the score of player 2,2
if the score of player 2 is more than the score of player 1, and0
in case of a draw.Example 1:
Input: player1 = [4,10,7,9], player2 = [6,5,2,3]
Output: 1
Explanation: The score of player1 is 4 + 10 + 27 + 29 = 46.
The score of player2 is 6 + 5 + 2 + 3 = 16.
Score of player1 is more than the score of player2, so, player1 is the winner, and the answer is 1.
Example 2:
Input: player1 = [3,5,7,6], player2 = [8,10,10,2]
Output: 2
Explanation: The score of player1 is 3 + 5 + 7 + 6 = 21.
The score of player2 is 8 + 10 + 210 + 22 = 42.
Score of player2 is more than the score of player1, so, player2 is the winner, and the answer is 2.
Example 3:
Input: player1 = [2,3], player2 = [4,1]
Output: 0
Explanation: The score of player1 is 2 + 3 = 5
The score of player2 is 4 + 1 = 5
The score of player1 equals to the score of player2, so, there is a draw, and the answer is 0.
Constraints:
n == player1.length == player2.length
1 <= n <= 1000
0 <= player1[i], player2[i] <= 10
public class Solution {
public int isWinner(int[] player1, int[] player2) {
int p1Score = 0;
int p2Score = 0;
int isTen = 0;
for (int score : player1) {
p1Score += (isTen > 0) ? 2 * score : score;
if (isTen > 0) {
isTen--;
}
if (score == 10) {
isTen = 2;
}
}
isTen = 0;
for (int score : player2) {
p2Score += (isTen > 0) ? 2 * score : score;
if (isTen > 0) {
isTen--;
}
if (score == 10) {
isTen = 2;
}
}
if (p1Score == p2Score) {
return 0;
} else if (p1Score > p2Score) {
return 1;
} else {
return 2;
}
}
}