Easy
You are given a 0-indexed m x n integer matrix grid. The width of a column is the maximum length of its integers.
grid = \[\[-10], [3], [12]], the width of the only column is 3 since -10 is of length 3.Return an integer array ans of size n where ans[i] is the width of the ith column.
The length of an integer x with len digits is equal to len if x is non-negative, and len + 1 otherwise.
Example 1:
Input: grid = [[1],[22],[333]]
Output: [3]
Explanation: In the 0th column, 333 is of length 3.
Example 2:
Input: grid = [[-15,1,3],[15,7,12],[5,6,-2]]
Output: [3,1,2]
Explanation:
In the 0th column, only -15 is of length 3.
In the 1st column, all integers are of length 1.
In the 2nd column, both 12 and -2 are of length 2.
Constraints:
m == grid.lengthn == grid[i].length1 <= m, n <= 100-109 <= grid[r][c] <= 109public class Solution {
public int[] findColumnWidth(int[][] grid) {
int[] ans = new int[grid[0].length];
for (int j = 0; j < grid[0].length; j++) {
int max = 1;
for (int[] ints : grid) {
int num = ints[j];
boolean neg = false;
if (num < 0) {
neg = true;
num *= -1;
}
int size = 0;
while (num > 0) {
num /= 10;
size++;
}
if (neg) {
size += 1;
}
max = Math.max(max, size);
}
ans[j] = max;
}
return ans;
}
}