LeetCode-in-Java

2621. Sleep

Easy

Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.

Example 1:

Input: millis = 100

Output: 100

Explanation: It should return a promise that resolves after 100ms. let t = Date.now(); sleep(100).then(() => { console.log(Date.now() - t); // 100 });

Example 2:

Input: millis = 200

Output: 200

Explanation: It should return a promise that resolves after 200ms.

Constraints:

Solution

async function sleep(millis: number): Promise<void> {
    await new Promise((resolve) => setTimeout(resolve, millis))
}

/*
 * let t = Date.now()
 * sleep(100).then(() => console.log(Date.now() - t)) // 100
 */

export { sleep }