LeetCode-in-Java

2600. K Items With the Maximum Sum

Easy

There is a bag that consists of items, each item has a number 1, 0, or -1 written on it.

You are given four non-negative integers numOnes, numZeros, numNegOnes, and k.

The bag initially contains:

• numOnes items with 1s written on them.
• numZeroes items with 0s written on them.
• numNegOnes items with -1s written on them.

We want to pick exactly k items among the available items. Return the maximum possible sum of numbers written on the items.

Example 1:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2

Output: 2

Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2. It can be proven that 2 is the maximum possible sum.

Example 2:

Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4

Output: 3

Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3. It can be proven that 3 is the maximum possible sum.

Constraints:

• 0 <= numOnes, numZeros, numNegOnes <= 50
• 0 <= k <= numOnes + numZeros + numNegOnes

Solution

@SuppressWarnings("java:S1172")
public class Solution {
    public int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {
        if (k <= numOnes) {
            return k;
        }
        if (k <= numOnes + numZeros) {
            return numOnes;
        }
        int remainingSum = k - (numOnes + numZeros);
        return numOnes - remainingSum;
    }
}

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