LeetCode-in-Java

2574. Left and Right Sum Differences

Easy

Given a 0-indexed integer array nums, find a 0-indexed integer array answer where:

• answer.length == nums.length.
• answer[i] = |leftSum[i] - rightSum[i]|.

Where:

• leftSum[i] is the sum of elements to the left of the index i in the array nums. If there is no such element, leftSum[i] = 0.
• rightSum[i] is the sum of elements to the right of the index i in the array nums. If there is no such element, rightSum[i] = 0.

Return the array answer.

Example 1:

Input: nums = [10,4,8,3]

Output: [15,1,11,22]

Explanation: The array leftSum is [0,10,14,22] and the array rightSum is [15,11,3,0]. The array answer is [|0 - 15|,|10 - 11|,|14 - 3|,|22 - 0|] = [15,1,11,22].

Example 2:

Input: nums = [1]

Output: [0]

Explanation: The array leftSum is [0] and the array rightSum is [0]. The array answer is [|0 - 0|] = [0].

Constraints:

• 1 <= nums.length <= 1000
• 1 <= nums[i] <= 105

Solution

public class Solution {
    public int[] leftRightDifference(int[] nums) {
        int ls = 0;
        int rs = 0;
        for (int i : nums) {
            rs += i;
        }
        for (int i = 0; i < nums.length; ++i) {
            ls += nums[i];
            rs -= nums[i];
            nums[i] = Math.abs(rs - (ls - nums[i]));
        }
        return nums;
    }
}

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