Medium
Given a 0-indexed integer array nums
of size n
and two integers lower
and upper
, return the number of fair pairs.
A pair (i, j)
is fair if:
0 <= i < j < n
, andlower <= nums[i] + nums[j] <= upper
Example 1:
Input: nums = [0,1,7,4,4,5], lower = 3, upper = 6
Output: 6
Explanation: There are 6 fair pairs: (0,3), (0,4), (0,5), (1,3), (1,4), and (1,5).
Example 2:
Input: nums = [1,7,9,2,5], lower = 11, upper = 11
Output: 1
Explanation: There is a single fair pair: (2,3).
Constraints:
1 <= nums.length <= 105
nums.length == n
-109 <= nums[i] <= 109
-109 <= lower <= upper <= 109
import java.util.Arrays;
public class Solution {
public long countFairPairs(int[] nums, int lower, int upper) {
Arrays.sort(nums);
long c1 = 0;
long c2 = 0;
int i = 0;
int j = nums.length - 1;
while (i < j) {
if (nums[i] + nums[j] <= upper) {
c1 = c1 + (j - i);
i++;
} else {
j--;
}
}
i = 0;
j = nums.length - 1;
while (i < j) {
if (nums[i] + nums[j] < lower) {
c2 = c2 + (j - i);
i++;
} else {
j--;
}
}
return c1 - c2;
}
}