LeetCode-in-Java
2347. Best Poker Hand
Easy
You are given an integer array ranks and a character array suits. You have 5 cards where the ith card has a rank of ranks[i] and a suit of suits[i].
The following are the types of poker hands you can make from best to worst:
"Flush": Five cards of the same suit."Three of a Kind": Three cards of the same rank."Pair": Two cards of the same rank."High Card": Any single card.
Return a string representing the best type of poker hand you can make with the given cards.
Note that the return values are case-sensitive.
Example 1:
Input: ranks = [13,2,3,1,9], suits = [“a”,”a”,”a”,”a”,”a”]
Output: “Flush”
Explanation: The hand with all the cards consists of 5 cards with the same suit, so we have a “Flush”.
Example 2:
Input: ranks = [4,4,2,4,4], suits = [“d”,”a”,”a”,”b”,”c”]
Output: “Three of a Kind”
Explanation: The hand with the first, second, and fourth card consists of 3 cards with the same rank, so we have a “Three of a Kind”.
Note that we could also make a “Pair” hand but “Three of a Kind” is a better hand.
Also note that other cards could be used to make the “Three of a Kind” hand.
Example 3:
Input: ranks = [10,10,2,12,9], suits = [“a”,”b”,”c”,”a”,”d”]
Output: “Pair”
Explanation: The hand with the first and second card consists of 2 cards with the same rank, so we have a “Pair”.
Note that we cannot make a “Flush” or a “Three of a Kind”.
Constraints:
ranks.length == suits.length == 51 <= ranks[i] <= 13'a' <= suits[i] <= 'd'- No two cards have the same rank and suit.
Solution
import java.util.HashMap;
public class Solution {
public String bestHand(int[] ranks, char[] suits) {
HashMap<Character, Integer> map = new HashMap<>();
for (char suit : suits) {
if (map.containsKey(suit)) {
map.put(suit, map.get(suit) + 1);
if (map.get(suit) == 5) {
return "Flush";
}
} else {
map.put(suit, 1);
}
}
String s = "";
HashMap<Integer, Integer> map2 = new HashMap<>();
for (int rank : ranks) {
if (map2.containsKey(rank)) {
map2.put(rank, map2.get(rank) + 1);
if (map2.get(rank) == 2) {
s = "Pair";
} else if (map2.get(rank) == 3) {
s = "Three of a Kind";
return s;
}
} else {
map2.put(rank, 1);
}
}
return s.isEmpty() ? "High Card" : s;
}
}