Hard
You are given two integers m
and n
that represent the height and width of a rectangular piece of wood. You are also given a 2D integer array prices
, where prices[i] = [hi, wi, pricei]
indicates you can sell a rectangular piece of wood of height hi
and width wi
for pricei
dollars.
To cut a piece of wood, you must make a vertical or horizontal cut across the entire height or width of the piece to split it into two smaller pieces. After cutting a piece of wood into some number of smaller pieces, you can sell pieces according to prices
. You may sell multiple pieces of the same shape, and you do not have to sell all the shapes. The grain of the wood makes a difference, so you cannot rotate a piece to swap its height and width.
Return the maximum money you can earn after cutting an m x n
piece of wood.
Note that you can cut the piece of wood as many times as you want.
Example 1:
Input: m = 3, n = 5, prices = [[1,4,2],[2,2,7],[2,1,3]]
Output: 19
Explanation: The diagram above shows a possible scenario. It consists of:
2 pieces of wood shaped 2 x 2, selling for a price of 2 * 7 = 14.
1 piece of wood shaped 2 x 1, selling for a price of 1 * 3 = 3.
1 piece of wood shaped 1 x 4, selling for a price of 1 * 2 = 2.
This obtains a total of 14 + 3 + 2 = 19 money earned.
It can be shown that 19 is the maximum amount of money that can be earned.
Example 2:
Input: m = 4, n = 6, prices = [[3,2,10],[1,4,2],[4,1,3]]
Output: 32
Explanation: The diagram above shows a possible scenario. It consists of:
3 pieces of wood shaped 3 x 2, selling for a price of 3 * 10 = 30.
1 piece of wood shaped 1 x 4, selling for a price of 1 * 2 = 2.
This obtains a total of 30 + 2 = 32 money earned.
It can be shown that 32 is the maximum amount of money that can be earned.
Notice that we cannot rotate the 1 x 4 piece of wood to obtain a 4 x 1 piece of wood.
Constraints:
1 <= m, n <= 200
1 <= prices.length <= 2 * 104
prices[i].length == 3
1 <= hi <= m
1 <= wi <= n
1 <= pricei <= 106
(hi, wi)
are pairwise distinct.public class Solution {
public long sellingWood(int m, int n, int[][] prices) {
// dp[i][j] = Maximum profit selling wood of size i*j
long[][] dp = new long[m][n];
for (int[] price : prices) {
dp[price[0] - 1][price[1] - 1] = Math.max(dp[price[0] - 1][price[1] - 1], price[2]);
}
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
// Cut Vertically
for (int k = 0; k < j; k++) {
dp[i][j] = Math.max(dp[i][j], dp[i][k] + dp[i][j - k - 1]);
}
// Cut Horizontally
for (int k = 0; k < i; k++) {
dp[i][j] = Math.max(dp[i][j], dp[k][j] + dp[i - k - 1][j]);
}
}
}
return dp[m - 1][n - 1];
}
}