LeetCode-in-Java

2299. Strong Password Checker II

Easy

A password is said to be strong if it satisfies all the following criteria:

• It has at least 8 characters.
• It contains at least one lowercase letter.
• It contains at least one uppercase letter.
• It contains at least one digit.
• It contains at least one special character. The special characters are the characters in the following string: "!@#$%^&*()-+".
• It does not contain 2 of the same character in adjacent positions (i.e., "aab" violates this condition, but "aba" does not).

Given a string password, return true if it is a strong password. Otherwise, return false.

Example 1:

Input: password = “IloveLe3tcode!”

Output: true

Explanation: The password meets all the requirements. Therefore, we return true.

Example 2:

Input: password = “Me+You–IsMyDream”

Output: false

Explanation: The password does not contain a digit and also contains 2 of the same character in adjacent positions. Therefore, we return false.

Example 3:

Input: password = “1aB!”

Output: false

Explanation: The password does not meet the length requirement. Therefore, we return false.

Constraints:

• 1 <= password.length <= 100
• password consists of letters, digits, and special characters: "!@#$%^&*()-+".

Solution

public class Solution {
    public boolean strongPasswordCheckerII(String password) {
        if (password.length() < 8) {
            return false;
        }
        boolean l = false;
        boolean u = false;
        boolean d = false;
        boolean s = false;
        String special = "!@#$%^&*()-+";
        char previous = '.';
        for (int i = 0; i != password.length(); i++) {
            char ch = password.charAt(i);
            if (ch == previous) {
                return false;
            }
            previous = ch;
            if (ch >= 'A' && ch <= 'Z') {
                u = true;
            } else if (ch >= 'a' && ch <= 'z') {
                l = true;
            } else if (ch >= '0' && ch <= '9') {
                d = true;
            } else if (special.indexOf(ch) != -1) {
                s = true;
            }
        }
        return l && u && d && s;
    }
}

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