LeetCode-in-Java
2278. Percentage of Letter in String
Easy
Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.
Example 1:
Input: s = “foobar”, letter = “o”
Output: 33
Explanation:
The percentage of characters in s that equal the letter ‘o’ is 2 / 6 * 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = “jjjj”, letter = “k”
Output: 0
Explanation:
The percentage of characters in s that equal the letter ‘k’ is 0%, so we return 0.
Constraints:
1 <= s.length <= 100sconsists of lowercase English letters.letteris a lowercase English letter.
Solution
public class Solution {
public int percentageLetter(String s, char letter) {
int count = 0;
int n = s.length();
for (int i = 0; i < n; i++) {
if (s.charAt(i) == letter) {
++count;
}
}
return (count * 100) / (n);
}
}