Medium
The bitwise AND of an array nums
is the bitwise AND of all integers in nums
.
nums = [1, 5, 3]
, the bitwise AND is equal to 1 & 5 & 3 = 1
.nums = [7]
, the bitwise AND is 7
.You are given an array of positive integers candidates
. Evaluate the bitwise AND of every combination of numbers of candidates
. Each number in candidates
may only be used once in each combination.
Return the size of the largest combination of candidates
with a bitwise AND greater than 0
.
Example 1:
Input: candidates = [16,17,71,62,12,24,14]
Output: 4
Explanation: The combination [16,17,62,24] has a bitwise AND of 16 & 17 & 62 & 24 = 16 > 0.
The size of the combination is 4.
It can be shown that no combination with a size greater than 4 has a bitwise AND greater than 0.
Note that more than one combination may have the largest size.
For example, the combination [62,12,24,14] has a bitwise AND of 62 & 12 & 24 & 14 = 8 > 0.
Example 2:
Input: candidates = [8,8]
Output: 2
Explanation: The largest combination [8,8] has a bitwise AND of 8 & 8 = 8 > 0.
The size of the combination is 2, so we return 2.
Constraints:
1 <= candidates.length <= 105
1 <= candidates[i] <= 107
public class Solution {
public int largestCombination(int[] candidates) {
int[] bits = new int[32];
for (int x : candidates) {
for (int i = 0; x != 0; i++, x >>= 1) {
bits[i] += x & 1;
}
}
int ans = 0;
for (int b : bits) {
ans = Math.max(ans, b);
}
return ans;
}
}