Medium
You are given an integer array matches
where matches[i] = [winneri, loseri]
indicates that the player winneri
defeated player loseri
in a match.
Return a list answer
of size 2
where:
answer[0]
is a list of all players that have not lost any matches.answer[1]
is a list of all players that have lost exactly one match.The values in the two lists should be returned in increasing order.
Note:
Example 1:
Input: matches = [[1,3],[2,3],[3,6],[5,6],[5,7],[4,5],[4,8],[4,9],[10,4],[10,9]]
Output: [[1,2,10],[4,5,7,8]]
Explanation: Players 1, 2, and 10 have not lost any matches. Players 4, 5, 7, and 8 each have lost one match. Players 3, 6, and 9 each have lost two matches. Thus, answer[0] = [1,2,10] and answer[1] = [4,5,7,8].
Example 2:
Input: matches = [[2,3],[1,3],[5,4],[6,4]]
Output: [[1,2,5,6],[]]
Explanation: Players 1, 2, 5, and 6 have not lost any matches. Players 3 and 4 each have lost two matches. Thus, answer[0] = [1,2,5,6] and answer[1] = [].
Constraints:
1 <= matches.length <= 105
matches[i].length == 2
1 <= winneri, loseri <= 105
winneri != loseri
matches[i]
are unique.import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class Solution {
public List<List<Integer>> findWinners(int[][] matches) {
Map<Integer, Integer> map = new HashMap<>();
List<Integer> list1 = new ArrayList<>();
List<Integer> list2 = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
for (int[] match : matches) {
int winner = match[0];
int loser = match[1];
map.putIfAbsent(winner, 0);
map.put(loser, map.getOrDefault(loser, 0) + 1);
}
for (Map.Entry<Integer, Integer> entry : map.entrySet()) {
if (entry.getValue() == 0) {
list1.add(entry.getKey());
}
if (entry.getValue() == 1) {
list2.add(entry.getKey());
}
}
Collections.sort(list1);
Collections.sort(list2);
res.add(list1);
res.add(list2);
return res;
}
}