LeetCode-in-Java
1907. Count Salary Categories
Medium
SQL Schema
Table: Accounts
+-------------+------+
| Column Name | Type |
+-------------+------+
| account_id | int |
| income | int |
+-------------+------+
account_id is the primary key for this table.
Each row contains information about the monthly income for one bank account.
Write an SQL query to report the number of bank accounts of each salary category. The salary categories are:
"Low Salary": All the salaries strictly less than$20000."Average Salary": All the salaries in the inclusive range[$20000, $50000]."High Salary": All the salaries strictly greater than$50000.
The result table must contain all three categories. If there are no accounts in a category, then report 0.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input:
Accounts table:
+------------+--------+
| account_id | income |
+------------+--------+
| 3 | 108939 |
| 2 | 12747 |
| 8 | 87709 |
| 6 | 91796 |
+------------+--------+
Output:
+----------------+----------------+
| category | accounts_count |
+----------------+----------------+
| Low Salary | 1 |
| Average Salary | 0 |
| High Salary | 3 |
+----------------+----------------+
Explanation:
Low Salary: Account 2.
Average Salary: No accounts.
High Salary: Accounts 3, 6, and 8.
Solution
# Write your MySQL query statement below
select 'Low Salary' as category, count(*) as accounts_count from accounts where income<20000
union
select 'Average Salary' as category, count(*) as accounts_count from accounts where income>=20000 and income<=50000
union
select 'High Salary' as category, count(*) as accounts_count from accounts where income>50000