Easy
There is a biker going on a road trip. The road trip consists of n + 1
points at different altitudes. The biker starts his trip on point 0
with altitude equal 0
.
You are given an integer array gain
of length n
where gain[i]
is the net gain in altitude between points i
and i + 1
for all (0 <= i < n)
. Return the highest altitude of a point.
Example 1:
Input: gain = [-5,1,5,0,-7]
Output: 1
Explanation: The altitudes are [0,-5,-4,1,1,-6]. The highest is 1.
Example 2:
Input: gain = [-4,-3,-2,-1,4,3,2]
Output: 0
Explanation: The altitudes are [0,-4,-7,-9,-10,-6,-3,-1]. The highest is 0.
Constraints:
n == gain.length
1 <= n <= 100
-100 <= gain[i] <= 100
public class Solution {
public int largestAltitude(int[] gain) {
int max = 0;
int[] altitudes = new int[gain.length + 1];
for (int i = 0; i < gain.length; i++) {
altitudes[i + 1] = altitudes[i] + gain[i];
max = Math.max(max, altitudes[i + 1]);
}
return max;
}
}