LeetCode-in-Java

1684. Count the Number of Consistent Strings

Easy

You are given a string allowed consisting of distinct characters and an array of strings words. A string is consistent if all characters in the string appear in the string allowed.

Return the number of consistent strings in the array words.

Example 1:

Input: allowed = “ab”, words = [“ad”,”bd”,”aaab”,”baa”,”badab”]

Output: 2

Explanation: Strings “aaab” and “baa” are consistent since they only contain characters ‘a’ and ‘b’.

Example 2:

Input: allowed = “abc”, words = [“a”,”b”,”c”,”ab”,”ac”,”bc”,”abc”]

Output: 7

Explanation: All strings are consistent.

Example 3:

Input: allowed = “cad”, words = [“cc”,”acd”,”b”,”ba”,”bac”,”bad”,”ac”,”d”]

Output: 4

Explanation: Strings “cc”, “acd”, “ac”, and “d” are consistent.

Constraints:

• 1 <= words.length <= 104
• 1 <= allowed.length <= 26
• 1 <= words[i].length <= 10
• The characters in allowed are distinct.
• words[i] and allowed contain only lowercase English letters.

Solution

public class Solution {
    public int countConsistentStrings(String allowed, String[] words) {
        int alwd = 0;
        int res = 0;
        for (int i = 0; i < allowed.length(); ++i) {
            alwd |= 1 << allowed.charAt(i);
        }
        for (String word : words) {
            int b = 0;
            for (int j = 0; j < word.length(); ++j) {
                b |= 1 << word.charAt(j);
            }
            if ((alwd | b) == alwd) {
                ++res;
            }
        }
        return res;
    }
}

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