Easy
Given a m x n
matrix grid
which is sorted in non-increasing order both row-wise and column-wise, return the number of negative numbers in grid
.
Example 1:
Input: grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]
Output: 8
Explanation: There are 8 negatives number in the matrix.
Example 2:
Input: grid = [[3,2],[1,0]]
Output: 0
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 100
-100 <= grid[i][j] <= 100
Follow up: Could you find an O(n + m)
solution?
public class Solution {
public int countNegatives(int[][] grid) {
int count = 0;
for (int[] row : grid) {
for (int v : row) {
if (v < 0) {
count++;
}
}
}
return count;
}
}