Medium
Given a list of folders folder
, return the folders after removing all sub-folders in those folders. You may return the answer in any order.
If a folder[i]
is located within another folder[j]
, it is called a sub-folder of it.
The format of a path is one or more concatenated strings of the form: '/'
followed by one or more lowercase English letters.
"/leetcode"
and "/leetcode/problems"
are valid paths while an empty string and "/"
are not.Example 1:
Input: folder = [“/a”,”/a/b”,”/c/d”,”/c/d/e”,”/c/f”]
Output: [“/a”,”/c/d”,”/c/f”]
Explanation: Folders “/a/b” is a subfolder of “/a” and “/c/d/e” is inside of folder “/c/d” in our filesystem.
Example 2:
Input: folder = [“/a”,”/a/b/c”,”/a/b/d”]
Output: [“/a”]
Explanation: Folders “/a/b/c” and “/a/b/d” will be removed because they are subfolders of “/a”.
Example 3:
Input: folder = [“/a/b/c”,”/a/b/ca”,”/a/b/d”]
Output: [“/a/b/c”,”/a/b/ca”,”/a/b/d”]
Constraints:
1 <= folder.length <= 4 * 104
2 <= folder[i].length <= 100
folder[i]
contains only lowercase letters and '/'
.folder[i]
always starts with the character '/'
.import java.util.ArrayList;
import java.util.Collections;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
public class Solution {
public List<String> removeSubfolders(String[] folder) {
Set<String> paths = new HashSet<>();
Collections.addAll(paths, folder);
List<String> res = new ArrayList<>();
for (String f : folder) {
int lastSlash = f.lastIndexOf("/");
boolean isSub = false;
while (lastSlash > 0) {
String upperDir = f.substring(0, lastSlash);
if (paths.contains(upperDir)) {
isSub = true;
break;
}
lastSlash = upperDir.lastIndexOf("/");
}
if (!isSub) {
res.add(f);
}
}
return res;
}
}