Easy
Balanced strings are those that have an equal quantity of 'L'
and 'R'
characters.
Given a balanced string s
, split it in the maximum amount of balanced strings.
Return the maximum amount of split balanced strings.
Example 1:
Input: s = “RLRRLLRLRL”
Output: 4
Explanation: s can be split into “RL”, “RRLL”, “RL”, “RL”, each substring contains same number of ‘L’ and ‘R’.
Example 2:
Input: s = “RLLLLRRRLR”
Output: 3
Explanation: s can be split into “RL”, “LLLRRR”, “LR”, each substring contains same number of ‘L’ and ‘R’.
Example 3:
Input: s = “LLLLRRRR”
Output: 1
Explanation: s can be split into “LLLLRRRR”.
Constraints:
1 <= s.length <= 1000
s[i]
is either 'L'
or 'R'
.s
is a balanced string.public class Solution {
public int balancedStringSplit(String s) {
int i = 0;
int balancedCount = 0;
int lCount = 0;
int rCount = 0;
while (i < s.length()) {
if (s.charAt(i) == 'L') {
lCount++;
} else {
rCount++;
}
i++;
if (lCount != 0 && lCount == rCount) {
lCount = 0;
rCount = 0;
balancedCount++;
}
}
return balancedCount;
}
}