LeetCode-in-Java

1195. Fizz Buzz Multithreaded

Medium

You have the four functions:

You are given an instance of the class FizzBuzz that has four functions: fizz, buzz, fizzbuzz and number. The same instance of FizzBuzz will be passed to four different threads:

Modify the given class to output the series [1, 2, "Fizz", 4, "Buzz", ...] where the ith token (1-indexed) of the series is:

Implement the FizzBuzz class:

Example 1:

Input: n = 15

Output: [1,2,”fizz”,4,”buzz”,”fizz”,7,8,”fizz”,”buzz”,11,”fizz”,13,14,”fizzbuzz”]

Example 2:

Input: n = 5

Output: [1,2,”fizz”,4,”buzz”]

Constraints:

Solution

import java.util.function.IntConsumer;

@SuppressWarnings("java:S1130")
public class FizzBuzz {
    private final int n;
    private int current;

    public FizzBuzz(int n) {
        this.n = n;
        this.current = 1;
    }

    // printFizz.run() outputs "fizz".
    public void fizz(Runnable printFizz) throws InterruptedException {
        synchronized (this) {
            while (current <= n) {
                if (current % 3 == 0 && current % 5 != 0) {
                    printFizz.run();
                    current += 1;
                    notifyAll();
                } else {
                    wait();
                }
            }
        }
    }

    // printBuzz.run() outputs "buzz".
    public void buzz(Runnable printBuzz) throws InterruptedException {
        synchronized (this) {
            while (current <= n) {
                if (current % 3 != 0 && current % 5 == 0) {
                    printBuzz.run();
                    current += 1;
                    notifyAll();
                } else {
                    wait();
                }
            }
        }
    }

    // printFizzBuzz.run() outputs "fizzbuzz".
    public void fizzbuzz(Runnable printFizzBuzz) throws InterruptedException {
        synchronized (this) {
            while (current <= n) {
                if (current % 15 == 0) {
                    printFizzBuzz.run();
                    current += 1;
                    notifyAll();
                } else {
                    wait();
                }
            }
        }
    }

    // printNumber.accept(x) outputs "x", where x is an integer.
    public void number(IntConsumer printNumber) throws InterruptedException {
        synchronized (this) {
            while (current <= n) {
                if (current % 3 != 0 && current % 5 != 0) {
                    printNumber.accept(current);
                    current += 1;
                    notifyAll();
                } else {
                    wait();
                }
            }
        }
    }
}