LeetCode-in-Java
1131. Maximum of Absolute Value Expression
Medium
Given two arrays of integers with equal lengths, return the maximum value of:
|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|
where the maximum is taken over all 0 <= i, j < arr1.length.
Example 1:
Input: arr1 = [1,2,3,4], arr2 = [-1,4,5,6]
Output: 13
Example 2:
Input: arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]
Output: 20
Constraints:
2 <= arr1.length == arr2.length <= 40000-10^6 <= arr1[i], arr2[i] <= 10^6
Solution
public class Solution {
public int maxAbsValExpr(int[] arr1, int[] arr2) {
if (arr1.length != arr2.length) {
return 0;
}
int max1 = Integer.MIN_VALUE;
int max2 = Integer.MIN_VALUE;
int max3 = Integer.MIN_VALUE;
int max4 = Integer.MIN_VALUE;
int min1 = Integer.MAX_VALUE;
int min2 = Integer.MAX_VALUE;
int min3 = Integer.MAX_VALUE;
int min4 = Integer.MAX_VALUE;
for (int i = 0; i < arr1.length; i++) {
max1 = Math.max(arr1[i] + arr2[i] + i, max1);
min1 = Math.min(arr1[i] + arr2[i] + i, min1);
max2 = Math.max(i - arr1[i] - arr2[i], max2);
min2 = Math.min(i - arr1[i] - arr2[i], min2);
max3 = Math.max(arr1[i] - arr2[i] + i, max3);
min3 = Math.min(arr1[i] - arr2[i] + i, min3);
max4 = Math.max(arr2[i] - arr1[i] + i, max4);
min4 = Math.min(arr2[i] - arr1[i] + i, min4);
}
return Math.max(Math.max(max1 - min1, max2 - min2), Math.max(max3 - min3, max4 - min4));
}
}