LeetCode-in-Java
1089. Duplicate Zeros
Easy
Given a fixed-length integer array arr, duplicate each occurrence of zero, shifting the remaining elements to the right.
Note that elements beyond the length of the original array are not written. Do the above modifications to the input array in place and do not return anything.
Example 1:
Input: arr = [1,0,2,3,0,4,5,0]
Output: [1,0,0,2,3,0,0,4]
Explanation: After calling your function, the input array is modified to: [1,0,0,2,3,0,0,4]
Example 2:
Input: arr = [1,2,3]
Output: [1,2,3]
Explanation: After calling your function, the input array is modified to: [1,2,3]
Constraints:
1 <= arr.length <= 1040 <= arr[i] <= 9
Solution
public class Solution {
public void duplicateZeros(int[] arr) {
int countZero = 0;
for (int k : arr) {
if (k == 0) {
countZero++;
}
}
int len = arr.length + countZero;
// We just need O(1) space if we scan from back
// i point to the original array, j point to the new location
int i = arr.length - 1;
int j = len - 1;
while (i < j) {
// copy twice when hit '0'
if (arr[i] == 0) {
if (j < arr.length) {
arr[j] = arr[i];
}
j--;
}
if (j < arr.length) {
arr[j] = arr[i];
}
i--;
j--;
}
}
}