LeetCode-in-Java

998. Maximum Binary Tree II

Medium

A maximum tree is a tree where every node has a value greater than any other value in its subtree.

You are given the root of a maximum binary tree and an integer val.

Just as in the previous problem, the given tree was constructed from a list a (root = Construct(a)) recursively with the following Construct(a) routine:

Note that we were not given a directly, only a root node root = Construct(a).

Suppose b is a copy of a with the value val appended to it. It is guaranteed that b has unique values.

Return Construct(b).

Example 1:

Input: root = [4,1,3,null,null,2], val = 5

Output: [5,4,null,1,3,null,null,2]

Explanation: a = [1,4,2,3], b = [1,4,2,3,5]

Example 2:

Input: root = [5,2,4,null,1], val = 3

Output: [5,2,4,null,1,null,3]

Explanation: a = [2,1,5,4], b = [2,1,5,4,3]

Example 3:

Input: root = [5,2,3,null,1], val = 4

Output: [5,2,4,null,1,3]

Explanation: a = [2,1,5,3], b = [2,1,5,3,4]

Constraints:

Solution

import com_github_leetcode.TreeNode;

/*
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
public class Solution {
    public TreeNode insertIntoMaxTree(TreeNode root, int val) {
        return insertIntoMaxTree2(root, val);
    }

    private TreeNode insertIntoMaxTree2(TreeNode root, int val) {
        if (root == null) {
            return new TreeNode(val);
        }
        if (root.val < val) {
            return new TreeNode(val, root, null);
        }
        root.right = this.insertIntoMaxTree2(root.right, val);
        return root;
    }
}