Medium
A maximum tree is a tree where every node has a value greater than any other value in its subtree.
You are given the root
of a maximum binary tree and an integer val
.
Just as in the previous problem, the given tree was constructed from a list a
(root = Construct(a)
) recursively with the following Construct(a)
routine:
a
is empty, return null
.a[i]
be the largest element of a
. Create a root
node with the value a[i]
.root
will be Construct([a[0], a[1], ..., a[i - 1]])
.root
will be Construct([a[i + 1], a[i + 2], ..., a[a.length - 1]])
.root
.Note that we were not given a
directly, only a root node root = Construct(a)
.
Suppose b
is a copy of a
with the value val
appended to it. It is guaranteed that b
has unique values.
Return Construct(b)
.
Example 1:
Input: root = [4,1,3,null,null,2], val = 5
Output: [5,4,null,1,3,null,null,2]
Explanation: a = [1,4,2,3], b = [1,4,2,3,5]
Example 2:
Input: root = [5,2,4,null,1], val = 3
Output: [5,2,4,null,1,null,3]
Explanation: a = [2,1,5,4], b = [2,1,5,4,3]
Example 3:
Input: root = [5,2,3,null,1], val = 4
Output: [5,2,4,null,1,3]
Explanation: a = [2,1,5,3], b = [2,1,5,3,4]
Constraints:
[1, 100]
.1 <= Node.val <= 100
1 <= val <= 100
import com_github_leetcode.TreeNode;
/*
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
public class Solution {
public TreeNode insertIntoMaxTree(TreeNode root, int val) {
return insertIntoMaxTree2(root, val);
}
private TreeNode insertIntoMaxTree2(TreeNode root, int val) {
if (root == null) {
return new TreeNode(val);
}
if (root.val < val) {
return new TreeNode(val, root, null);
}
root.right = this.insertIntoMaxTree2(root.right, val);
return root;
}
}