Easy
Every valid email consists of a local name and a domain name, separated by the '@'
sign. Besides lowercase letters, the email may contain one or more '.'
or '+'
.
"alice@leetcode.com"
, "alice"
is the local name, and "leetcode.com"
is the domain name.If you add periods '.'
between some characters in the local name part of an email address, mail sent there will be forwarded to the same address without dots in the local name. Note that this rule does not apply to domain names.
"alice.z@leetcode.com"
and "alicez@leetcode.com"
forward to the same email address.If you add a plus '+'
in the local name, everything after the first plus sign will be ignored. This allows certain emails to be filtered. Note that this rule does not apply to domain names.
"m.y+name@email.com"
will be forwarded to "my@email.com"
.It is possible to use both of these rules at the same time.
Given an array of strings emails
where we send one email to each emails[i]
, return the number of different addresses that actually receive mails.
Example 1:
Input: emails = [“test.email+alex@leetcode.com”,”test.e.mail+bob.cathy@leetcode.com”,”testemail+david@lee.tcode.com”]
Output: 2
Explanation: “testemail@leetcode.com” and “testemail@lee.tcode.com” actually receive mails.
Example 2:
Input: emails = [“a@leetcode.com”,”b@leetcode.com”,”c@leetcode.com”]
Output: 3
Constraints:
1 <= emails.length <= 100
1 <= emails[i].length <= 100
emails[i]
consist of lowercase English letters, '+'
, '.'
and '@'
.emails[i]
contains exactly one '@'
character.'+'
character.".com"
suffix.import java.util.HashSet;
import java.util.Set;
public class Solution {
public int numUniqueEmails(String[] emails) {
Set<String> set = new HashSet<>();
for (String s : emails) {
StringBuilder sb = new StringBuilder();
int i = 0;
while (i < s.length()) {
char c = s.charAt(i);
if (c == '+' || c == '@') {
sb.append('@');
i = s.indexOf("@") + 1;
sb.append(s.substring(i));
break;
} else if (c != '.') {
sb.append(c);
}
i++;
}
set.add(sb.toString());
}
return set.size();
}
}