LeetCode-in-Java

910. Smallest Range II

Medium

You are given an integer array nums and an integer k.

For each index i where 0 <= i < nums.length, change nums[i] to be either nums[i] + k or nums[i] - k.

The score of nums is the difference between the maximum and minimum elements in nums.

Return the minimum score of nums after changing the values at each index.

Example 1:

Input: nums = [1], k = 0

Output: 0

Explanation: The score is max(nums) - min(nums) = 1 - 1 = 0.

Example 2:

Input: nums = [0,10], k = 2

Output: 6

Explanation: Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.

Example 3:

Input: nums = [1,3,6], k = 3

Output: 3

Explanation: Change nums to be [4, 6, 3]. The score is max(nums) - min(nums) = 6 - 3 = 3.

Constraints:

• 1 <= nums.length <= 104
• 0 <= nums[i] <= 104
• 0 <= k <= 104

Solution

import java.util.Arrays;

public class Solution {
    public int smallestRangeII(int[] nums, int k) {
        Arrays.sort(nums);
        int n = nums.length;
        int ans = nums[n - 1] - nums[0];
        int min = nums[0] + k;
        int max = nums[n - 1] - k;
        for (int i = 0; i < n - 1; i++) {
            int mx = Math.max(max, nums[i] + k);
            int mi = Math.min(min, nums[i + 1] - k);
            ans = Math.min(ans, mx - mi);
        }
        return ans;
    }
}

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