Easy
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:
'a'
maps to ".-"
,'b'
maps to "-..."
,'c'
maps to "-.-."
, and so on.For convenience, the full table for the 26
letters of the English alphabet is given below:
[”.-“,”-…”,”-.-.”,”-..”,”.”,”..-.”,”–.”,”….”,”..”,”.—”,”-.-“,”.-..”,”–”,”-.”,”—”,”.–.”,”–.-“,”.-.”,”…”,”-“,”..-“,”…-“,”.–”,”-..-“,”-.–”,”–..”]
Given an array of strings words
where each word can be written as a concatenation of the Morse code of each letter.
"cab"
can be written as "-.-..--..."
, which is the concatenation of "-.-."
, ".-"
, and "-..."
. We will call such a concatenation the transformation of a word.Return the number of different transformations among all words we have.
Example 1:
Input: words = [“gin”,”zen”,”gig”,”msg”]
Output: 2
Explanation: The transformation of each word is:
“gin” -> “–…-.”
“zen” -> “–…-.”
“gig” -> “–…–.”
“msg” -> “–…–.”
There are 2 different transformations: “–…-.” and “–…–.”.
Example 2:
Input: words = [“a”]
Output: 1
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 12
words[i]
consists of lowercase English letters.import java.util.HashSet;
import java.util.Set;
public class Solution {
public int uniqueMorseRepresentations(String[] words) {
String[] morse = {
".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....", "..", ".---", "-.-", ".-..",
"--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-",
"-.--", "--.."
};
Set<String> set = new HashSet<>();
for (String word : words) {
StringBuilder temp = new StringBuilder();
for (char c : word.toCharArray()) {
temp.append(morse[c - 'a']);
}
set.add(temp.toString());
}
return set.size();
}
}