LeetCode-in-Java

690. Employee Importance

Medium

You have a data structure of employee information, including the employee’s unique ID, importance value, and direct subordinates’ IDs.

You are given an array of employees employees where:

Given an integer id that represents an employee’s ID, return the total importance value of this employee and all their direct and indirect subordinates.

Example 1:

Input: employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1

Output: 11

Explanation:

Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3.

They both have an importance value of 3.

Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11.

Example 2:

Input: employees = [[1,2,[5]],[5,-3,[]]], id = 5

Output: -3

Explanation:

Employee 5 has an importance value of -3 and has no direct subordinates.

Thus, the total importance value of employee 5 is -3.

Constraints:

Solution

import com_github_leetcode.Employee;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

/*
// Definition for Employee.
class Employee {
    public int id;
    public int importance;
    public List<Integer> subordinates;
};
*/
public class Solution {
    public int getImportance(List<Employee> employees, int id) {
        Map<Integer, Employee> map = new HashMap<>();
        for (Employee emp : employees) {
            map.put(emp.id, emp);
        }
        return calculateImportance(id, map);
    }

    private int calculateImportance(int id, Map<Integer, Employee> map) {
        Employee employee = map.get(id);
        int sum = employee.importance;
        for (int sub : employee.subordinates) {
            sum += calculateImportance(sub, map);
        }
        return sum;
    }
}