Hard
Nearly everyone has used the Multiplication Table. The multiplication table of size m x n is an integer matrix mat where mat[i][j] == i * j (1-indexed).
Given three integers m, n, and k, return the kth smallest element in the m x n multiplication table.
Example 1:

Input: m = 3, n = 3, k = 5
Output: 3
Explanation: The 5th smallest number is 3.
Example 2:

Input: m = 2, n = 3, k = 6
Output: 6
Explanation: The 6th smallest number is 6.
Constraints:
1 <= m, n <= 3 * 1041 <= k <= m * npublic class Solution {
public int findKthNumber(int m, int n, int k) {
int lo = 1;
int hi = m * n;
while (lo < hi) {
int mid = lo + (hi - lo) / 2;
int col = n;
int row = 1;
int count = 0;
while (row <= m && col >= 1) {
int val = row * col;
if (val > mid) {
col--;
} else {
count += col;
row++;
}
}
if (count < k) {
lo = mid + 1;
} else {
hi = mid;
}
}
return lo;
}
}