Medium
Given the root
of a binary tree, construct a 0-indexed m x n
string matrix res
that represents a formatted layout of the tree. The formatted layout matrix should be constructed using the following rules:
height
and the number of rows m
should be equal to height + 1
.n
should be equal to 2height+1 - 1
.res[0][(n-1)/2]
).res[r][c]
, place its left child at res[r+1][c-2height-r-1]
and its right child at res[r+1][c+2height-r-1]
.""
.Return the constructed matrix res
.
Example 1:
Input: root = [1,2]
Output: [[””,”1”,””], [“2”,””,””]]
Example 2:
Input: root = [1,2,3,null,4]
Output: [[””,””,””,”1”,””,””,””], [””,”2”,””,””,””,”3”,””], [””,””,”4”,””,””,””,””]]
Constraints:
[1, 210]
.-99 <= Node.val <= 99
[1, 10]
.import com_github_leetcode.TreeNode;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
/*
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
public class Solution {
public List<List<String>> printTree(TreeNode root) {
List<List<String>> result = new LinkedList<>();
int height = root == null ? 1 : getHeight(root);
int columns = (int) (Math.pow(2, height) - 1);
List<String> row = new ArrayList<>();
for (int i = 0; i < columns; i++) {
row.add("");
}
for (int i = 0; i < height; i++) {
result.add(new ArrayList<>(row));
}
populateResult(root, result, 0, height, 0, columns - 1);
return result;
}
private void populateResult(
TreeNode root, List<List<String>> result, int row, int totalRows, int i, int j) {
if (row == totalRows || root == null) {
return;
}
result.get(row).set((i + j) / 2, Integer.toString(root.val));
populateResult(root.left, result, row + 1, totalRows, i, (i + j) / 2 - 1);
populateResult(root.right, result, row + 1, totalRows, (i + j) / 2 + 1, j);
}
private int getHeight(TreeNode root) {
if (root == null) {
return 0;
}
return 1 + Math.max(getHeight(root.left), getHeight(root.right));
}
}