Easy
SQL Schema
Table: Cinema
+----------------+----------+
| Column Name | Type |
+----------------+----------+
| id | int |
| movie | varchar |
| description | varchar |
| rating | float |
+----------------+----------+
id is the primary key for this table.
Each row contains information about the name of a movie, its genre, and its rating.
rating is a 2 decimal places float in the range [0, 10]
Write an SQL query to report the movies with an odd-numbered ID and a description that is not "boring"
.
Return the result table ordered by rating
in descending order.
The query result format is in the following example.
Example 1:
Input: Cinema table: +—-+————+————-+——–+ | id | movie | description | rating | +—-+————+————-+——–+ | 1 | War | great 3D | 8.9 | | 2 | Science | fiction | 8.5 | | 3 | irish | boring | 6.2 | | 4 | Ice song | Fantacy | 8.6 | | 5 | House card | Interesting | 9.1 | +—-+————+————-+——–+
Output:
+----+------------+-------------+--------+
| id | movie | description | rating |
+----+------------+-------------+--------+
| 5 | House card | Interesting | 9.1 |
| 1 | War | great 3D | 8.9 |
+----+------------+-------------+--------+
Explanation:
We have three movies with odd-numbered IDs: 1, 3, and 5. The movie with ID = 3 is boring so we do not
include it in the answer.
# Write your MySQL query statement below
SELECT *
FROM cinema
WHERE description != 'boring'
AND ID % 2 = 1
ORDER BY rating desc;