Medium
Given an integer array nums
, return the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle.
Example 1:
Input: nums = [2,2,3,4]
Output: 3
Explanation: Valid combinations are: 2,3,4 (using the first 2) 2,3,4 (using the second 2) 2,2,3
Example 2:
Input: nums = [4,2,3,4]
Output: 4
Constraints:
1 <= nums.length <= 1000
0 <= nums[i] <= 1000
public class Solution {
public int triangleNumber(int[] nums) {
int n;
int max = 0;
int[] count = new int[1001];
for (int i : nums) {
count[i]++;
max = Math.max(max, i);
}
count[0] = 0;
int idx = 0;
for (int i = 1; i <= max; ++i) {
for (int j = 0; j < count[i]; ++j, ++idx) {
nums[idx] = i;
}
count[i] += count[i - 1];
}
n = idx;
int r = 0;
for (int i = 0; i < n - 2; ++i) {
for (int j = i + 1; j < n - 1; ++j) {
if (nums[i] + nums[j] > max) {
r += (n - j) * (n - j - 1) / 2;
break;
}
r += count[nums[i] + nums[j] - 1] - j - 1;
}
}
return r;
}
}