Easy
We define a harmonious array as an array where the difference between its maximum value and its minimum value is exactly 1
.
Given an integer array nums
, return the length of its longest harmonious subsequence among all its possible subsequences.
A subsequence of array is a sequence that can be derived from the array by deleting some or no elements without changing the order of the remaining elements.
Example 1:
Input: nums = [1,3,2,2,5,2,3,7]
Output: 5
Explanation: The longest harmonious subsequence is [3,2,2,2,3].
Example 2:
Input: nums = [1,2,3,4]
Output: 2
Example 3:
Input: nums = [1,1,1,1]
Output: 0
Constraints:
1 <= nums.length <= 2 * 104
-109 <= nums[i] <= 109
import java.util.Arrays;
public class Solution {
public int findLHS(int[] nums) {
Arrays.sort(nums);
int max = 0;
int lastN = 0;
int curN = 1;
int cur = nums[0];
for (int i = 1; i < nums.length; i++) {
if (nums[i] > cur) {
if (lastN > 0 && curN > 0 && lastN + curN > max) {
max = lastN + curN;
}
// if diff more than 1, don't count
lastN = nums[i] - cur == 1 ? curN : 0;
curN = 1;
cur = nums[i];
} else {
curN++;
}
}
if (lastN > 0 && curN > 0 && lastN + curN > max) {
max = lastN + curN;
}
return max;
}
}