Medium
Given the root
of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus the sum of all keys greater than the original key in BST.
As a reminder, a binary search tree is a tree that satisfies these constraints:
Example 1:
Input: root = [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]
Output: [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]
Example 2:
Input: root = [0,null,1]
Output: [1,null,1]
Constraints:
[0, 104]
.-104 <= Node.val <= 104
root
is guaranteed to be a valid binary search tree.Note: This question is the same as 1038: https://leetcode.com/problems/binary-search-tree-to-greater-sum-tree/
import com_github_leetcode.TreeNode;
/*
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
public class Solution {
public TreeNode convertBST(TreeNode root) {
if (root != null) {
postOrder(root, 0);
}
return root;
}
private int postOrder(TreeNode node, int val) {
int newVal = 0;
if (node.right != null) {
newVal += postOrder(node.right, val);
}
newVal += newVal == 0 ? val + node.val : node.val;
node.val = newVal;
if (node.left != null) {
newVal = postOrder(node.left, newVal);
}
return newVal;
}
}