LeetCode-in-Java

522. Longest Uncommon Subsequence II

Medium

Given an array of strings strs, return the length of the longest uncommon subsequence between them. If the longest uncommon subsequence does not exist, return -1.

An uncommon subsequence between an array of strings is a string that is a subsequence of one string but not the others.

A subsequence of a string s is a string that can be obtained after deleting any number of characters from s.

• For example, "abc" is a subsequence of "aebdc" because you can delete the underlined characters in "aebdc" to get "abc". Other subsequences of "aebdc" include "aebdc", "aeb", and "" (empty string).

Example 1:

Input: strs = [“aba”,”cdc”,”eae”]

Output: 3

Example 2:

Input: strs = [“aaa”,”aaa”,”aa”]

Output: -1

Constraints:

• 2 <= strs.length <= 50
• 1 <= strs[i].length <= 10
• strs[i] consists of lowercase English letters.

Solution

public class Solution {
    public int findLUSlength(String[] strs) {
        int maxUncommonLen = -1;
        for (int indx1 = 0; indx1 < strs.length; indx1++) {
            boolean isCommon = false;
            for (int indx2 = 0; indx2 < strs.length; indx2++) {
                if (indx2 != indx1 && isSubSequence(strs[indx1], strs[indx2])) {
                    isCommon = true;
                    break;
                }
            }
            if (!isCommon) {
                maxUncommonLen = Math.max(maxUncommonLen, strs[indx1].length());
            }
        }
        return maxUncommonLen;
    }

    private boolean isSubSequence(String str1, String str2) {
        int indx1 = 0;
        for (int indx2 = 0; indx2 < str2.length(); indx2++) {
            if (str1.charAt(indx1) == str2.charAt(indx2)) {
                indx1++;
            }
            if (indx1 == str1.length()) {
                return true;
            }
        }
        return indx1 == str1.length();
    }
}

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