Medium
Given an m x n
matrix mat
, return an array of all the elements of the array in a diagonal order.
Example 1:
Input: mat = [[1,2,3],[4,5,6],[7,8,9]]
Output: [1,2,4,7,5,3,6,8,9]
Example 2:
Input: mat = [[1,2],[3,4]]
Output: [1,2,3,4]
Constraints:
m == mat.length
n == mat[i].length
1 <= m, n <= 104
1 <= m * n <= 104
-105 <= mat[i][j] <= 105
public class Solution {
public int[] findDiagonalOrder(int[][] mat) {
int m = mat.length;
int n = mat[0].length;
int[] output = new int[m * n];
int idx = 0;
for (int diag = 0; diag <= m + n - 2; ++diag) {
if (diag % 2 == 0) {
for (int k = Math.max(0, diag - m + 1); k <= Math.min(diag, n - 1); ++k) {
output[idx++] = mat[diag - k][k];
}
} else {
for (int k = Math.max(0, diag - n + 1); k <= Math.min(diag, m - 1); ++k) {
output[idx++] = mat[k][diag - k];
}
}
}
return output;
}
}