LeetCode-in-Java
495. Teemo Attacking
Easy
Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds. More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]. If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack.
You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration.
Return the total number of seconds that Ashe is poisoned.
Example 1:
Input: timeSeries = [1,4], duration = 2
Output: 4
Explanation: Teemo’s attacks on Ashe go as follows: - At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. - At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
Example 2:
Input: timeSeries = [1,2], duration = 2
Output: 3
Explanation:
Teemo’s attacks on Ashe go as follows:
-
At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
-
At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
Constraints:
1 <= timeSeries.length <= 1040 <= timeSeries[i], duration <= 107timeSeriesis sorted in non-decreasing order.
Solution
public class Solution {
public int findPoisonedDuration(int[] timeSeries, int duration) {
if (duration == 0) {
return 0;
}
int start = timeSeries[0];
int end = timeSeries[0] + duration - 1;
int poisonDuration = end - start + 1;
for (int i = 1; i < timeSeries.length; i++) {
if (timeSeries[i] <= end) {
poisonDuration += (duration - (end - timeSeries[i] + 1));
end += (duration - (end - timeSeries[i] + 1));
} else {
start = timeSeries[i];
end = timeSeries[i] + duration - 1;
poisonDuration += end - start + 1;
}
}
return poisonDuration;
}
}