LeetCode-in-Java

477. Total Hamming Distance

Medium

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given an integer array nums, return the sum of Hamming distances between all the pairs of the integers in nums.

Example 1:

Input: nums = [4,14,2]

Output: 6

Explanation: In binary representation, the 4 is 0100, 14 is 1110, and 2 is 0010 (just showing the four bits relevant in this case). The answer will be: HammingDistance(4, 14) + HammingDistance(4, 2) + HammingDistance(14, 2) = 2 + 2 + 2 = 6.

Example 2:

Input: nums = [4,14,4]

Output: 4

Constraints:

• 1 <= nums.length <= 104
• 0 <= nums[i] <= 109
• The answer for the given input will fit in a 32-bit integer.

Solution

public class Solution {
    public int totalHammingDistance(int[] nums) {
        int ans = 0;
        int n = nums.length;
        for (int i = 0; i < 32; i++) {
            int ones = 0;
            for (int k : nums) {
                ones += ((k >> i) & 1);
            }
            ans = ans + (ones * (n - ones));
        }
        return ans;
    }
}

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