LeetCode-in-Java

453. Minimum Moves to Equal Array Elements

Medium

Given an integer array nums of size n, return the minimum number of moves required to make all array elements equal.

In one move, you can increment n - 1 elements of the array by 1.

Example 1:

Input: nums = [1,2,3]

Output: 3

Explanation: Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]

Example 2:

Input: nums = [1,1,1]

Output: 0

Constraints:

• n == nums.length
• 1 <= nums.length <= 105
• -109 <= nums[i] <= 109
• The answer is guaranteed to fit in a 32-bit integer.

Solution

public class Solution {
    public int minMoves(int[] nums) {
        int min = nums[0];
        int sum = nums[0];
        // determining the total sum and smallest element of the input array
        for (int i = 1; i <= nums.length - 1; i++) {
            sum += nums[i];
            min = Math.min(min, nums[i]);
        }
        return sum - (min * nums.length);
    }
}

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