LeetCode-in-Java
401. Binary Watch
Easy
A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59). Each LED represents a zero or one, with the least significant bit on the right.
- For example, the below binary watch reads
"4:51".
Given an integer turnedOn which represents the number of LEDs that are currently on, return all possible times the watch could represent. You may return the answer in any order.
The hour must not contain a leading zero.
- For example,
"01:00"is not valid. It should be"1:00".
The minute must be consist of two digits and may contain a leading zero.
- For example,
"10:2"is not valid. It should be"10:02".
Example 1:
Input: turnedOn = 1
Output: [“0:01”,”0:02”,”0:04”,”0:08”,”0:16”,”0:32”,”1:00”,”2:00”,”4:00”,”8:00”]
Example 2:
Input: turnedOn = 9
Output: []
Constraints:
0 <= turnedOn <= 10
Solution
import java.util.ArrayList;
import java.util.List;
public class Solution {
public List<String> readBinaryWatch(int turnedOn) {
List<String> times = new ArrayList<>();
for (int hour = 0; hour <= 11; hour++) {
for (int minutes = 0; minutes <= 59; minutes++) {
readBinaryWatchHelper(turnedOn, times, hour, minutes);
}
}
return times;
}
private void readBinaryWatchHelper(
int turnedOn, List<String> selectedTimes, int hour, int minutes) {
if (isValidTime(turnedOn, hour, minutes)) {
selectedTimes.add(getTimeString(hour, minutes));
}
}
private String getTimeString(int hour, int minutes) {
StringBuilder time = new StringBuilder();
time.append(hour);
time.append(':');
if (minutes < 10) {
time.append('0');
}
time.append(minutes);
return time.toString();
}
private boolean isValidTime(int turnedOn, int hour, int minutes) {
int counter = 0;
while (hour != 0) {
if ((hour & 1) == 1) {
counter++;
}
hour >>>= 1;
}
if (counter > turnedOn) {
return false;
}
while (minutes != 0) {
if ((minutes & 1) == 1) {
counter++;
}
minutes >>>= 1;
}
return counter == turnedOn;
}
}