Medium
We are playing the Guessing Game. The game will work as follows:
1
and n
.x
, you will pay x
dollars. If you run out of money, you lose the game.Given a particular n
, return the minimum amount of money you need to guarantee a win regardless of what number I pick.
Example 1:
Input: n = 10
Output: 16
Explanation:
The winning strategy is as follows:
- The range is [1,10]. Guess 7.
- If this is my number, your total is $0. Otherwise, you pay $7.
- If my number is higher, the range is [8,10]. Guess 9.
- If this is my number, your total is $7. Otherwise, you pay $9.
- If my number is higher, it must be 10. Guess 10. Your total is $7 + $9 = $16.
- If my number is lower, it must be 8. Guess 8. Your total is $7 + $9 = $16.
- If my number is lower, the range is [1,6]. Guess 3.
- If this is my number, your total is $7. Otherwise, you pay $3.
- If my number is higher, the range is [4,6]. Guess 5.
- If this is my number, your total is $7 + $3 = $10. Otherwise, you pay $5.
- If my number is higher, it must be 6. Guess 6. Your total is $7 + $3 + $5 = $15.
- If my number is lower, it must be 4. Guess 4. Your total is $7 + $3 + $5 = $15.
- If my number is lower, the range is [1,2]. Guess 1.
- If this is my number, your total is $7 + $3 = $10. Otherwise, you pay $1.
- If my number is higher, it must be 2. Guess 2. Your total is $7 + $3 + $1 = $11.
The worst case in all these scenarios is that you pay $16. Hence, you only need $16 to guarantee a win.
Example 2:
Input: n = 1
Output: 0
Explanation: There is only one possible number, so you can guess 1 and not have to pay anything.
Example 3:
Input: n = 2
Output: 1
Explanation:
There are two possible numbers, 1 and 2.
- Guess 1.
- If this is my number, your total is $0. Otherwise, you pay $1.
- If my number is higher, it must be 2. Guess 2. Your total is $1.
The worst case is that you pay $1.
Constraints:
1 <= n <= 200
@SuppressWarnings("java:S135")
public class Solution {
int[][] matrix;
public int getMoneyAmount(int n) {
matrix = new int[n + 1][n + 1];
return get(1, n);
}
private int get(int min, int max) {
if (max - min < 3) {
return max - min <= 0 ? 0 : max - 1;
}
if (matrix[min][max] != 0) {
return matrix[min][max];
}
int select = max - 3;
int minRes = Integer.MAX_VALUE;
int res;
int end = min + ((max - min) >> 1) - 1;
int cnt = 0;
while (true) {
res = select + Math.max(get(min, select - 1), get(select + 1, max));
if (res > minRes) {
cnt++;
if (cnt >= 3) {
break;
}
}
if (res < minRes) {
minRes = res;
}
select--;
if (select <= end) {
break;
}
}
matrix[min][max] = minRes;
return minRes;
}
}