LeetCode-in-Java

335. Self Crossing

Hard

You are given an array of integers distance.

You start at point (0,0) on an X-Y plane and you move distance[0] meters to the north, then distance[1] meters to the west, distance[2] meters to the south, distance[3] meters to the east, and so on. In other words, after each move, your direction changes counter-clockwise.

Return true if your path crosses itself, and false if it does not.

Example 1:

Input: distance = [2,1,1,2]

Output: true

Example 2:

Input: distance = [1,2,3,4]

Output: false

Example 3:

Input: distance = [1,1,1,1]

Output: true

Constraints:

Solution

public class Solution {
    public boolean isSelfCrossing(int[] x) {
        if (x.length < 4) {
            return false;
        }
        for (int i = 3; i < x.length; i++) {
            if (x[i - 1] <= x[i - 3] && x[i] >= x[i - 2]) {
                return true;
            }
            if (i > 4
                    && x[i] >= x[i - 2] - x[i - 4]
                    && x[i - 1] >= x[i - 3] - x[i - 5]
                    && x[i - 1] <= x[i - 3]
                    && x[i - 2] >= x[i - 4]) {
                return true;
            }
            if (i > 3 && x[i - 1] == x[i - 3] && x[i] >= x[i - 2] - x[i - 4]) {
                return true;
            }
        }
        return false;
    }
}