Easy
Given an integer array nums
and an integer k
, return true
if there are two distinct indices i
and j
in the array such that nums[i] == nums[j]
and abs(i - j) <= k
.
Example 1:
Input: nums = [1,2,3,1], k = 3
Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1
Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2
Output: false
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
0 <= k <= 105
import java.util.HashMap;
import java.util.Map;
public class Solution {
public boolean containsNearbyDuplicate(int[] nums, int k) {
Map<Integer, Integer> map = new HashMap<>();
int len = nums.length;
for (int i = 0; i < len; i++) {
Integer index = map.put(nums[i], i);
if (index != null && Math.abs(index - i) <= k) {
return true;
}
}
return false;
}
}